Mathematically and technically proven Gravity based perpetual motion machine.

[Vikram gupta]

As per sketch a 2 meter long tube is mounted on the left arm of a seesaw and this see saw is balanced due to counterweight.there is a 10 kg mass ball located in the in rest position in the tube.
See the link.

https://youtu.be/1raDr-qRtrg


Now seesaw is balanced at 180 degree angle.when I tilt it this balanced seesaw then the ball fall down from 2 meter height and hit with upper part of tube .but interesting after hitting the seesaw will get back it's initial position without any external influence.so ball will again fall from 2 meter height.in this way the ball will fall down twicely but the main interesting point is that the input energy is almost zero as there is no torque due to counterweight.
There will be a lock mechanism to prevent the falling of counterweight at the time of tilting.
The ball will fall down after getting a certain angle as a pin will work to hold the ball to prevent it from sliding along tube at the time of tilting.
If there is no energy as a input as seesaw is balanced and torque is same then output is ,using mgh formula
Mgh= 10*10*2=200 joule at the time of tilting.
Mgh=10*10*2=200 joule at the time of reversing.

So total output is 400 joule but input will be almost free due to equilibrium position of seesaw.
Input will be very minimal due to counterweight and equilibrium position.

[Rob Beckers]

Hi Vikram,

Your energy input is not quite zero: The effective center of gravity is between the ball and the counterweight is somewhere between the two. You move that center of gravity up by moving up the side with the ball, that is your energy input. The ball moving over and back in the pipe is just a distraction moving the center of gravity to the left and back to the right of the point of rotation, at the end of the process you're back where you started even if you don't extract any energy (and you're out the energy you put in to move up the center of gravity).

If this process truly yielded more than you put in it would repeat indefinitely, and in fact speed up since there is no energy extraction.

-RoB-

[Vikram gupta]

Hello sir,
The device is just to understand the concept but it is being proven mathematically.
See the attached sketch.
As per sketch there is a 2 meter long tube which is mounted very near to fulcrum.the 1 meter part of this tube is mounted below fulcrum and another is above fulcrum.
The weight of ball is 10 kg and counterweig ht is also 10 kg.but I will take counterweight 12 kg.
Due to 12 kg counterweight the device will be in Vertical position.
So now I will have to tilt the device from more 90 degree.
When I tilt it the ball fall down from 2 meter height and it will again fall down from 2 meter height at the time of reversing.
So input is using mgh formula
Mgh=2*10*1=20 Joule
But output
10*10*2=200 Joule
Again10*102=200 Joule
So total output is 400 Joule
Another important point
The counterweight is also a ball so when 10 kg ball fall down from 2 meter height then the counterweight ball also bounce so this output will also be added.
It will be 100 Joule.
Now total output will be 500 Joule.
When counterweight ball jump in the tube it will also work to providing momentum as the counterweight will become massless for a moment.

https://youtu.be/TQr-MR2yj_U

Two piston generator
on each side of long tube will work to extract energy to move the device again and again.
Though it will be an Oscillating device but my main purpose is to get more output than input.
If I am wrong then correct me.
Vikramhttp://https://youtu.be/TQr-MR2yj_U

[Laurie Forbes]

Your demonstration is evidence of nothing as, as Rob mentioned, you are adding energy to the device when you push on the container holding the ball. If your device was "over-unity" (perpetual motion) that input would not be necessary and the device would oscillate on its own without stopping. When you get it to do that, let us know...